sandy wrote:
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For all numbers n, n* = 32-n
column A: (n*)*
column B: n
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This kind of question (which I call a Strange Operator question) looks tricky, so let's see what happens when we plug in some values of n.
Try n = 0column A: (n*)* = (32 -
0)* = 32* = 32 - 32 =
0 column B: n =
0Here, the two columns are equal.
Try n = 10column A: (n*)* = (32 -
10)* = 22* = 32 - 22 =
10 column B: n =
10Here, the two columns are equal.
Try n = 33column A: (n*)* = (32 -
33)* = (-1)* = 32 - (-1) =
33 column B: n =
33Here, the two columns are equal.
Try n = -5column A: (n*)* = (32 -
-5)* = 37* = 32 - (37) =
-5 column B: n =
-5Here, the two columns are equal.
Well, it certainly seems like the two columns are always equal.
So, let's go with answer choice
Cheers,
Brent