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Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
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Location: India
WE:Education (Education)
Height [m]h[/m] (in meters) of a ball thrown upwards is given by equat
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06 Mar 2021, 05:11
06 Mar 2021, 05:11
00:00
Question Stats:
75% (02:01) correct
25% (01:20) wrong based on 20 sessions
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Height \(h\) (in meters) of a ball thrown upwards is given by equation \(h = -3(t - 6)^2 + 108\)
(A) Quantity A is greater
(B) Quantity B is greater
(C) The two quantities are equal
(D) The relationship cannot be determined from the information given
Quantity A |
Quantity B |
Height of ball 3.5 seconds after it was launched |
Height of ball 2 seconds after it reaches maximum height |
(A) Quantity A is greater
(B) Quantity B is greater
(C) The two quantities are equal
(D) The relationship cannot be determined from the information given
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: Height [m]h[/m] (in meters) of a ball thrown upwards is given by equat
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06 Mar 2021, 23:31
06 Mar 2021, 23:31
2
OA Explanation
\(h = -3(t - 6)^2 + 108\)
x-coordinates of the vertex of parabola is \(6\)
y-coordinate of the vertex of parabola (Max. point) is \(108\)
Col. A: Value of \(y\) when \(x = 3.5\)
Col. B: Value of \(y\) when \(x = (6 + 2) = 8\)
Col. A: \(89.25\)
Col. B: \(96\)
Hence, option B
\(h = -3(t - 6)^2 + 108\)
x-coordinates of the vertex of parabola is \(6\)
y-coordinate of the vertex of parabola (Max. point) is \(108\)
Col. A: Value of \(y\) when \(x = 3.5\)
Col. B: Value of \(y\) when \(x = (6 + 2) = 8\)
Col. A: \(89.25\)
Col. B: \(96\)
Hence, option B
Re: Height [m]h[/m] (in meters) of a ball thrown upwards is given by equat
[#permalink]
11 Mar 2021, 02:43
11 Mar 2021, 02:43
x value is substitute at t,right?
for QB,
h=-3(2-6)^2+108= -3*(-4)^2+108=-3*16+108=60....
how your QB h=96?
for QB,
h=-3(2-6)^2+108= -3*(-4)^2+108=-3*16+108=60....
how your QB h=96?
