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If p ≠ 0 and p = (2pq − q^2)^(1/2), then in terms of q, p =
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06 Mar 2021, 06:42
06 Mar 2021, 06:42
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If p ≠ 0 and \(p = \sqrt{2pq − q^2}\), then in terms of q, p =
(A) q
(B) q^2
(C) 2q
(D) –2q
(E) q/4
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
(A) q
(B) q^2
(C) 2q
(D) –2q
(E) q/4
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Joined: 10 Apr 2015
Posts: 6218
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Re: If p ≠ 0 and p = (2pq − q^2)^(1/2), then in terms of q, p =
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06 Mar 2021, 07:11
06 Mar 2021, 07:11
1
Carcass wrote:
If p ≠ 0 and \(p = \sqrt{2pq − q^2}\), then in terms of q, p =
(A) q
(B) q^2
(C) 2q
(D) –2q
(E) q/4
(A) q
(B) q^2
(C) 2q
(D) –2q
(E) q/4
Given: \(p = \sqrt{2pq − q^2}\)
Square both sides to get: p² = 2pq - q²
Set equation equal to zero: p² - 2pq + q² = 0 [NOTE: I did this because we have a quadratic equation]
Factor: (p - q)(p - q) = 0
So, we can conclude that p - q = 0, which means p = q
Answer: A
Cheers,
Brent
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Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
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Re: If p 0 and p = (2pq q^2)^(1/2), then in terms of q, p =
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03 Sep 2022, 04:16
03 Sep 2022, 04:16
1
Given that p ≠ 0 and \(p = \sqrt{2pq − q^2}\) and we need to find the value of p in terms of q
\(p = \sqrt{2pq − q^2}\)
Squaring both the sides we get
\(p^2 = (\sqrt{2pq − q^2})^2\)
=> \(p^2 = 2pq − q^2\)
=> \(p^2 - 2pq + q^2\) = 0
=> \((p-q)^2\) = 0
=> p = q
So, Answer will be A
Hope it helps!
\(p = \sqrt{2pq − q^2}\)
Squaring both the sides we get
\(p^2 = (\sqrt{2pq − q^2})^2\)
=> \(p^2 = 2pq − q^2\)
=> \(p^2 - 2pq + q^2\) = 0
=> \((p-q)^2\) = 0
=> p = q
So, Answer will be A
Hope it helps!
