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Re: p^2 or -p^2 [#permalink]
1
Carcass wrote:
I think the book assumed what you just said brent

It reports A


In order for the answer to be A, we'd need some condition that says p ≠ 0.

I've changed the official answer to D.
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Re: p^2 or -p^2 [#permalink]
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:student_man: :student_man:

A killing machine!
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Re: p^2 or -p^2 [#permalink]
case 1 -

let p=0
p^2=0
-p^2=0
(Two are equal)

case 2 -
let p=1
p^2=1
-p^2=-1

A is greater

Answer - D
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Re: p^2 or -p^2 [#permalink]
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