GeminiHeat wrote:
Jeramiah invests his savings of $120,000 by dividing it between two interest-earning accounts. He puts 3/4 of his savings in an account that earns lower interest and 1/4 of his savings in an account that earns higher interest. He has no other accounts that earn interest and he makes $3,636 in interest by the end of the year. If one account earns 2 percent annual interest, and both accounts are compounded semiannually, what percent interest does the other account earn?
A. 3
B. 4
C. 5
D. 6
E. 7
\(C.I = P(1 + \frac{r}{100n})^{nt} - P\)
Don't worry we will not be using this formula!Let us solve this using S.I
\($120,000\) is divided into two Principals of \($90,000\) (with lower rate of interest) and \($30,000\) (with higher rate of interest)
Notice, the option choices are all greater than \(2\)%
This means, \($90,000\) was invested at an interest rate of \(2\)%So, S.I \(= \frac{(90,000)(2)(1)}{100} = $1800\)
Now, \($30,000\) must give us a return of \(3636- 1800 = $1826\) at \(r\)% rate of interest in a year
i.e. \(1836 = \frac{(30,000)(r)(1)}{100}\)
\(r = 6.12\)%
Hence, option D