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Three photographers, Lisa, Mike and Norm, take photos of a wedding. Th
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09 Apr 2021, 05:17
09 Apr 2021, 05:17
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Three photographers, Lisa, Mike and Norm, take photos of a wedding. The total of Lisa and Mikes photos is 50 less than the sum of Mike's and Norms. If Norms photos number 10 more than twice the number of Lisa's photos, then how many photos did Norm Take?
A. 40
B. 50
C. 60
D. 80
E. 90
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. 40
B. 50
C. 60
D. 80
E. 90
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: Three photographers, Lisa, Mike and Norm, take photos of a wedding. Th
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09 Apr 2021, 05:48
09 Apr 2021, 05:48
1
Carcass wrote:
Three photographers, Lisa, Mike and Norm, take photos of a wedding. The total of Lisa and Mikes photos is 50 less than the sum of Mike's and Norms. If Norms photos number 10 more than twice the number of Lisa's photos, then how many photos did Norm Take?
A. 40
B. 50
C. 60
D. 80
E. 90
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. 40
B. 50
C. 60
D. 80
E. 90
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Here's a solution using 1 variable
Norms photos number 10 more than twice the number of Lisa's photos
Let x = the number of photographs that Lisa took.
So, 2x + 10 = the number of photographs that Norm took.
The total of Lisa and Mikes photos is 50 less than the sum of Mike's and Norms
We can write: (# of Lisa's photos) + (# of Mike's photos) = (# of Mike's photos) + (# of Norm's photos) - 50
Subtract (# of Mike's photos) from both sides to get: (# of Lisa's photos) = (# of Norm's photos) - 50
Plug in pre-defined values to get: (x) = (2x + 10) - 50
Simplify: x = 2x - 40
Solve: x = 40
How many photos did Norm Take?
2x + 10 = the number of photographs that Norm took.
So, 2x + 10 = 2(40) + 10 = 90
Answer: E
Cheers,
Brent
Re: Three photographers, Lisa, Mike and Norm, take photos of a wedding. Th
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10 Apr 2021, 01:15
10 Apr 2021, 01:15
2
L+M = M+N-50
i.e. L = N-50
Also N = 10+2L
i.e. L = (10+2L)-50
i.e. L = 40
i.e. N = 90
Answer: Option E
i.e. L = N-50
Also N = 10+2L
i.e. L = (10+2L)-50
i.e. L = 40
i.e. N = 90
Answer: Option E
