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The age of Mr. Chetan in 2002 was 1/90 of his birth year. What is his
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13 Apr 2021, 05:57
13 Apr 2021, 05:57
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The age of Mr. Chetan in 2002 was 1/90 of his birth year. What is his age in 2006?
A. 30
B. 28
C. 26
D. 24
E. 22
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. 30
B. 28
C. 26
D. 24
E. 22
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: The age of Mr. Chetan in 2002 was 1/90 of his birth year. What is his
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13 Apr 2021, 06:20
13 Apr 2021, 06:20
Carcass wrote:
The age of Mr. Chetan in 2002 was 1/90 of his birth year. What is his age in 2006?
A. 30
B. 28
C. 26
D. 24
E. 22
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. 30
B. 28
C. 26
D. 24
E. 22
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Let x = Chetan's age IN 2002
This means 2002 - x = Chetan's BIRTH YEAR
The age of Mr. Chetan in 2002 was 1/90 of his birth year.
We can write: x = (1/90)(2002 - x)
To eliminate the fraction, multiply both sides of the equation by 90 to get: 90x = (2002 - x)
Add x to both sides: 91x = 2002
Solve: x = 2002/91 = 22
So, Chetan was 22 years old in 2002
What is his age in 2006?
If Chetan was 22 years old in 2002, then Chetan's age in 2006 will be 26
Answer: C
Re: The age of Mr. Chetan in 2002 was 1/90 of his birth year. What is his
[#permalink]
13 Apr 2021, 09:39
13 Apr 2021, 09:39
1
If the year is x, then
2002−x=x/90
180180−90x=x
91x=180180
x=1980
Age in 2006=> 2006-1980=26
2002−x=x/90
180180−90x=x
91x=180180
x=1980
Age in 2006=> 2006-1980=26
