GeminiHeat wrote:
Two circles, one with radius 10 inches and the other with radius 4 inches, are tangent at point Q. Two insects start crawling at the same time from point Q: one along the larger circle at 3π inches per minute, the other along the smaller circle at 2.5π inches per minute. How much time has elapsed when the two insects meet again at point Q?
(A) 15 minutes
(B) 30 minutes
(C) 40 minutes
(D) 1 hour
(E) 1 hour, 20 minutes
Distance to be covered on larger circle
= 2π(10) = 20πDistance to be covered on smaller circle
= 2π(4) = 8πSince, both the insects have to be back at point Q, we must take the LCM of these distances i.e.
40πNow, the relative speed between these two insects
= 3π - 2.5π = 0.5πTime
= \frac{40π}{0.5π} = 80 minutes i.e. 1 hour 20 minutes
Hence, option E