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Let's rewrite all terms with the same base, and let's make 2 the common base. Given: 4^a x 4^b = 2(8^3) Rewrite 4 and 8 as powers of 2: (2^2)^a x (2^2)^b = 2((2^3)^3) Simplify: 2^(2a) x 2^(2b) = (2)(2^9) Simplify again: 2^(2a + 2b) = 2^10 Since the bases are now equal, we can conclude that 2a + 2b = 10 Divide both sides by 2 to get: a + b = 5
Re: If 4^a*4^b=2(8^3), what is the value of a+b?
[#permalink]
27 Apr 2021, 03:58
In this case, I do not see the advantage of distributing the 2 into (a+b) since the question is asking what that quantity is. We can consider it a single variable in this case, right?
After making the same base to equate the exponents, ended with
2(a+b)=10
.
Same answer in the end, but eliminating a potential place for error.