Carcass wrote:
John would have reduced the time it took him to drive from his home to a certain store by 1/3 if he had increased his average speed by 15 miles per hour. What was John's actual average speed, in miles per hour, when he drove from his home to the store?
(A) 25
(B) 30
(C) 40
(D) 45
(E) 50
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITIONGRE - Math BookLet's start with a
word equation: (John's travel time at faster speed) = 2/3
(John's regular travel time) Let
r = John's regular speedSo,
r+15 = John's faster speedLet
d = the distance traveled at regular speedSo
d = the distance traveled at regular speedtime = distance/speedSo, we get:
d/(r + 15) = (2/3)
(d/r) Rewrite as: d/(r + 15)= 2d/3r
Cross multiply: (d)(3r) = 2d(r + 15)
Expand: 3rd = 2rd + 30d
Rearrange to get: rd = 30d
Divide both sides by d to get:
r = 30Answer: B