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O is the center of the circle with radius r
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05 May 2021, 01:53
05 May 2021, 01:53
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78% (01:37) correct
21% (01:39) wrong based on 37 sessions
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GRE O is the center of the circle with radius r.jpg [ 14.19 KiB | Viewed 2163 times ]
O is the center of the circle of radius r
Quantity A |
Quantity B |
\(OP\) |
\(\frac{r}{\sqrt{2}}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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O is the center of the circle with radius r
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05 May 2021, 10:36
05 May 2021, 10:36
1
Carcass wrote:
Attachment:
GRE O is the center of the circle with radius r.jpg
O is the center of the circle of radius r
Quantity A |
Quantity B |
\(OP\) |
\(\frac{r}{\sqrt{2}}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
OP is perpendicular bisector of a right isosceles triangle with two sides as \(r\) and the hypotenuse as \(\sqrt{2}r\)
OP bisects the base into two equal parts i.e. \(\frac{r}{\sqrt{2}}\)
Apply Pythagoras theorem to find the length of OP:
\(r^2 = (\frac{r}{\sqrt{2}})^2 + OP^2\)
\(OP = \frac{r}{\sqrt{2}}\)
Clearly, Col. A = Col. B
Hence, option C
Re: O is the center of the circle with radius r
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17 Jun 2024, 18:46
17 Jun 2024, 18:46
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