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A, B, C, D, E, F, G, and H are all integers, listed in order of increa
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11 May 2021, 03:41
11 May 2021, 03:41
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A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to \(5^{12}\) and \(5^{13}\), respectively, what is the value of A?
A. \(-24(5^{12})\)
B. \(-23(5^{12})\)
C. \(-24(5^6)\)
D. \(23(5^{12})\)
E. \(24(5^{12})\)
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. \(-24(5^{12})\)
B. \(-23(5^{12})\)
C. \(-24(5^6)\)
D. \(23(5^{12})\)
E. \(24(5^{12})\)
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: A, B, C, D, E, F, G, and H are all integers, listed in order of increa
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11 May 2021, 05:47
11 May 2021, 05:47
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Carcass wrote:
A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to \(5^{12}\) and \(5^{13}\), respectively, what is the value of A?
A. \(-24(5^{12})\)
B. \(-23(5^{12})\)
C. \(-24(5^6)\)
D. \(23(5^{12})\)
E. \(24(5^{12})\)
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. \(-24(5^{12})\)
B. \(-23(5^{12})\)
C. \(-24(5^6)\)
D. \(23(5^{12})\)
E. \(24(5^{12})\)
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
H = 5^13
G = 5^12
Distance between H and G = 5^13 - 5^12
= 5^12(5^1 - 1)
= (5^12)(4)
= (4)(5^12)
So, F = 5^12 - (4)(5^12)
E = 5^12 - (4)(5^12) - (4)(5^12)
D = 5^12 - (4)(5^12) - (4)(5^12) - (4)(5^12)
C = 5^12 - (4)(5^12) - (4)(5^12) - (4)(5^12) - (4)(5^12)
B = 5^12 - (4)(5^12) - (4)(5^12) - (4)(5^12) - (4)(5^12) - (4)(5^12)
A = 5^12 - (4)(5^12) - (4)(5^12) - (4)(5^12) - (4)(5^12) - (4)(5^12) - (4)(5^12)
So, A = 5^12 - [(4)(5^12) + (4)(5^12) + (4)(5^12) + (4)(5^12) + (4)(5^12) + (4)(5^12)]
= 5^12 - (24)(5^12)
= (1)(5^12) - (24)(5^12)
= (-23)(5^12)
= Answer choice B
Cheers,
Brent
gmatclubot
Re: A, B, C, D, E, F, G, and H are all integers, listed in order of increa [#permalink]
11 May 2021, 05:47
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