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x+y=1/6
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17 May 2021, 15:05
17 May 2021, 15:05
1
Expert Reply
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Question Stats:
63% (01:08) correct
36% (00:58) wrong based on 19 sessions
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\(x+y=\frac{1}{6}
\)
\(3x+2y=\frac{1}{6}
\)
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
\)
\(3x+2y=\frac{1}{6}
\)
Quantity A |
Quantity B |
x |
y |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
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Re: x+y=1/6
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18 May 2021, 08:09
18 May 2021, 08:09
1
Solving the equations we get
\(x+y=\frac{1}{6}\)
\(3x+2y=\frac{1}{6}\)
Lets multiple the first equation by 3 we get
\(3x+3y=\frac{3}{6}\) ....(1)
\(3x+2y=\frac{1}{6}\) ....(2)
(1) - (2) we get
3x + 3y - 3x - 2y = \(\frac{3}{6} - \frac{1}{6}\) = \(\frac{2}{6}\)
=> y = \(\frac{2}{6}\)
Using \(x+y=\frac{1}{6}\), we get
x + \(\frac{2}{6}\) = \(\frac{1}{6}\)
=> x = \(\frac{1}{6}\) - \(\frac{2}{6}\) = -\(\frac{1}{6}\)
Clearly y > x => Quantity B > Quantity A
So, Answer will be B
Hope it helps!
\(x+y=\frac{1}{6}\)
\(3x+2y=\frac{1}{6}\)
Lets multiple the first equation by 3 we get
\(3x+3y=\frac{3}{6}\) ....(1)
\(3x+2y=\frac{1}{6}\) ....(2)
(1) - (2) we get
3x + 3y - 3x - 2y = \(\frac{3}{6} - \frac{1}{6}\) = \(\frac{2}{6}\)
=> y = \(\frac{2}{6}\)
Using \(x+y=\frac{1}{6}\), we get
x + \(\frac{2}{6}\) = \(\frac{1}{6}\)
=> x = \(\frac{1}{6}\) - \(\frac{2}{6}\) = -\(\frac{1}{6}\)
Clearly y > x => Quantity B > Quantity A
So, Answer will be B
Hope it helps!
Re: x+y=1/6
[#permalink]
18 May 2021, 08:40
18 May 2021, 08:40
1
Solution:
x+y=\(\frac{1}{6} \)i.e. y=\(\frac{1}{6} \)-x
Substitute the value of y in the below equation
3x+2y=\(\frac{1}{6} \)
3x+\(\frac{1}{3} \)-2x=\(\frac{1}{6} \)
x=-\(\frac{1}{6} \)
-\(\frac{1}{6} \)+y=\(\frac{1}{6} \)
y=\(\frac{2}{6} \)=\(\frac{1}{3} \)
IMO B
Hope this helps!
x+y=\(\frac{1}{6} \)i.e. y=\(\frac{1}{6} \)-x
Substitute the value of y in the below equation
3x+2y=\(\frac{1}{6} \)
3x+\(\frac{1}{3} \)-2x=\(\frac{1}{6} \)
x=-\(\frac{1}{6} \)
-\(\frac{1}{6} \)+y=\(\frac{1}{6} \)
y=\(\frac{2}{6} \)=\(\frac{1}{3} \)
IMO B
Hope this helps!
