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In the figure above the square
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08 Jun 2021, 09:26
08 Jun 2021, 09:26
Expert Reply
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Question Stats:
85% (01:00) correct
14% (00:52) wrong based on 14 sessions
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In the figure above the square has two sides which are tangent to the circle. If the area of the circle is 4a²π, what is the area of the square?
A. 2a²
B. 4a
C. 4a²
D. 16a²
E. 64a²
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Re: In the figure above the square
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08 Jun 2021, 09:32
08 Jun 2021, 09:32
Carcass wrote:
In the figure above the square has two sides which are tangent to the circle. If the area of the circle is 4a²π, what is the area of the square?
A. 2a²
B. 4a
C. 4a²
D. 16a²
E. 64a²
The area of the circle is 4a²π
Area of circle = π(radius)²
= 4a²π
= π4a²
= π(2a)²
So, the radius = 2a
This means the diameter = 4a (diameter is TWICE the radius)
What is the area of the square?
Each side of the square has length 4a
Area of square = side²
= (4a )²
= 16a²
= D
Cheers,
Brent
gmatclubot
Re: In the figure above the square [#permalink]
08 Jun 2021, 09:32
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