Carcass wrote:
What is area of the sector ACBO in the circle above with center O, if the radius of the circle is 6 and the length of the arc ACB is 2π?
A. \(6\pi\)
B. \(6\pi - 6\)
C. \(6\pi - 9\)
D. \(6\pi-\frac{25}{2}\)
E. \(6\pi-9\sqrt{3}\)
Circumference = 2π(radius)
Given: radius is 6
So, circumference = 2π(6) =
12πWe're told the arc ACB has length 2π
2π/
12π =
1/6.
So, the arc represents
1/6 of the circle's entire circumference
This also means
sector ACBO represents 1/6 of the circle's areaArea of circle = π(radius)²
So, area of this circle = π(6)² = 36π
So, the area of sector ACBO =
1/6 of 36π
= 6π
Answer: A
Cheers,
Brent