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sqrt 16+9

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Carcass
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sqrt 16+9 [#permalink] New post   18 Jun 2021, 01:27
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Question Stats:

88% (00:16) correct 11% (00:37) wrong based on 18 sessions

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Quantity A
Quantity B
\(\sqrt{16+9}\)
\( \sqrt{16} + \sqrt{9} \)



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Pranaygre
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Re: sqrt 16+9 [#permalink] New post   18 Jun 2021, 02:06
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Quantity A:
\sqrt{16+9} = \sqrt{25} = 5

Quantity B:
\sqrt{16} + \sqrt{9} = 3+4=7

quant A < quant B

option B is correct
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Re: sqrt 16+9 [#permalink] New post   18 Jun 2021, 02:07
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Quantity A : Sqrt(16 + 9) = Sqrt(25) = 5

Quantity B : Sqrt(16) + Sqrt(9) = 4 + 3 = 7

Ans : B is greater
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sqrt 16+9 [#permalink] New post   19 Jul 2024, 00:48
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Wanted to answer faster so I chose the wrong answer. xD

Simply, use the EDMAS rule always while answering these types of questions.

Exponents come first (Unless brackets are mentioned in the question use BODMAS) we can write sqrt/16+9 = (16+9) ^1/2

On the other hand, we can write sqrt/16 + sqrt/9 =4+3=7.

Squaring both sides, we get 16+9 =25
7^2 =49

B>A. :)
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