This is a poorly constructed question. Not an ETS material. We may have to assume that all the nos are distinct.
Let's say those are \(N1, N2, ... N11\) in ascending order. So median value will be \(N6\)
The sum of the least \(6\) numbers is \(35\). So \(N1+N2+...+N6 = 35\) _________(1)
The sum of the greatest \(6\) numbers is \(125\). So \(N6+N7+...+N11 = 125\) __________(2)
By adding both the equation, we will get \(N1 + N2 + ... + N11 + N6 = 160\) (\(N6\) is in both so will be taken twice) ________(3)
The sum of the \(11\) numbers are \(142\)
\(N1 + N2 + ... + N11 = 142\) _________(4)
\((3) - (4)\)
\(N6 = 18 = median\)
arjunbir wrote:
can anyone please help me with the solution?
thank you