KarunMendiratta wrote:
Set A:
a,b,c,d,eSet B:
23a−6,23b−6,23c−6,23d−6,23e−6If the standard deviation of Set B is 12.5, then what is the standard deviation of Set A?
Key concept #1: Adding or subtracting the same number from every number in a set does not change the standard deviationKey concept #2: If every number in a set is multiplied by k, then the new standard deviation = (k)(old standard deviation)Let S = the standard deviation of
a,b,c,d,e By concept #2, the standard deviation of
23a,23b,23c,23d,23e =23SBy concept #1, the standard deviation of
23a−6,23b−6,23c−6,23d−6,23e−6 =23SIf the standard deviation of Set B is 12.5, we can write:
23S=12.5Multiply both sides of the equation by
32 to get:
S=18.75Since S represents the standard deviation of Set A, the answer is
18.75