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If x+y/x-y = 4/3
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29 Apr 2019, 01:33
29 Apr 2019, 01:33
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Question Stats:
72% (01:45) correct
27% (01:17) wrong based on 37 sessions
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If \(\frac{x+y}{x-y} = \frac{4}{3}\) and \(x \neq 0\), then what percentage (to the nearest integer) of x + 3y is x – 3y ?
(A) 20%
(B) 25%
(C) 30%
(D) 35%
(E) 40%
(A) 20%
(B) 25%
(C) 30%
(D) 35%
(E) 40%
Re: If x+y/x-y = 4/3
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13 Jul 2021, 10:43
13 Jul 2021, 10:43
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This is a tricky problem, so let's start by breaking it into two parts:
x+y/x-y = 4/3
If we cross multiply we get:
3x+3y = 4x - 4y
7y = x
^This will help us later, but first, let's move on to the second part.
What percentage (to the nearest integer) of x + 3y is x – 3y ???
Let "p" equal the percent we are looking for such that
(p /100)(x+3y) = x – 3y
If we divide by (x+3y) we get:
(p /100) = (x – 3y)/(x+3y)
Substituting in 7y for x, we have:
(p /100) = (7y – 3y)/(7y+3y) = 4y / 10 y = 0.4
Multiply by 100 to get:
p = 40 which happens to be answer choice E
x+y/x-y = 4/3
If we cross multiply we get:
3x+3y = 4x - 4y
7y = x
^This will help us later, but first, let's move on to the second part.
What percentage (to the nearest integer) of x + 3y is x – 3y ???
Let "p" equal the percent we are looking for such that
(p /100)(x+3y) = x – 3y
If we divide by (x+3y) we get:
(p /100) = (x – 3y)/(x+3y)
Substituting in 7y for x, we have:
(p /100) = (7y – 3y)/(7y+3y) = 4
Multiply by 100 to get:
p = 40 which happens to be answer choice E
