Carcass wrote:
If \(|y| ≤ - 4x\) and |\(3x - 4| = 2x + 6\), what is the value of x?
A. \(-3\)
B. \(\frac{-1}{3}\)
C. \(\frac{-2}{5}\)
D. \(\frac{1}{3}\)
E. \(10\)
First of all , thanks for this question that made me upset for a while. It's not that much easy. It must be at least mid level question.
Note:
|y| means the ultimate value is positive.
Given \(|y| \leq-4x\)
So, -4x is positive. It clearly indicates that x is negative.
we have |3x-4| = 2x + 6
Case 1:
3x - 4 is positive .
3x - 4 = 2x + 6
x = 10
Case 2 :
(3x - 4) is negative.
-3x + 4 = 2x + 6
x = - \(\frac{2}{5}\)
Thus x = - 2/5 as it meets out condition.
The best answer is C.