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Re: In the correctly-performed addition above, each letter repre [#permalink]
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This should be a bit less complicated.

Look at the units column. C + B + A = B. Therefore A + C = 10. Why? Because for B plus something else nonzero to be B, it must be adding 10, e.g, 5 + 10 = 15. So A and C together sum to 10.


Looking in the tens column, we see the same scenario. B + A = A. B is nonzero, but it can't be 10. However, since we had to carry one from the ones column, B MUST BE 9.

Finally, the hundreds column shows us that A must be one less than B, because again we carried a one from the tens and it yielded B. So A + 1 = B. Therefore, A MUST BE 8.

Remember we already established that A + C = 10? That means 8 + C = 10. Therefore C MUST BE 2.

The answer is B) 2.




GreenlightTestPrep wrote:

In the correctly-performed addition above, each letter represents a different non-zero digit. What is the value of C?

A) 1
B) 2
C) 3
D) 4
E) 5
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Re: In the correctly-performed addition above, each letter repre [#permalink]
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from the unit's digit, we can see that
A+B+C=10+B, as it is the only possible way we can add a digit (B) to something and get back the same digit
A+C=10

and in the ten's digit
1+B+A=10+A, once again the same reason as above
B=9

hundred's digit
1+A = B = 9
A=8

then coming back to the unit's digit equation
A+C=10
C=2

which is B
You can even verify the solution by substituting.
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Re: In the correctly-performed addition above, each letter repre [#permalink]
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Re: In the correctly-performed addition above, each letter repre [#permalink]
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