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Re: An office has 6 employees. The manager must create a committ [#permalink]
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Expert Reply
Sawant91 wrote:
Answer is B

As manager is going to select a committee, then 5C2 =10

Is is correct or it should be 6C2=20?



The manager is not part of employees, so it will be 6C3
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Re: An office has 6 employees. The manager must create a committ [#permalink]
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Answer: B
Selection of 3 out of 6:
A: 6C3 = 6*5*4*3! / 3! * 3! = 20
B: 40
B is bigger than A.
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Re: An office has 6 employees. The manager must create a committ [#permalink]
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An office has 6 employees. The CEO must create a committee consisting [#permalink]
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An office has 6 employees. The CEO must create a committee consisting of three of them.

Quantity A
Quantity B
Number of different committees possible
40



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


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Re: An office has 6 employees. The CEO must create a committee consisting [#permalink]
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6C3

\(\frac{6!}{3!(6-3)!}=\frac{6*5*4*3*2*1}{3*2*1*3*2*1}= 20\)


B is the answer
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Re: An office has 6 employees. The CEO must create a committee consisting [#permalink]
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