Carcass wrote:
Attachment:
GRE in the sum.jpg
In the sum above, if X and Y each denote one of the digits from 0 to 9, inclusive, then X=
(A) 9
(B) 5
(C) 3
(D) 1
(E) 0
One of the approach could be;Any 3 digit number ABC can be written as 100A + 10B + C, and any 2 digit number AB can be written as 10A + BYX7 = 100y + 10x + 7
6Y = 60 + y
Y7X = 100y + 70 + X
i.e. (100y + 10x + 7) + (60 + y) = 100y + 70 + X
Put the value of X as 10x as in YZ7;
(100y + 10x + 7) + (60 + y) = 100y + 70 + 10x
7 + 60 + y = 70
y = 3
i.e. YX7 = 300 + 10x + 7 = 3X7
60 + y = 60 + 3 = 63
Y7X = 300 + 70 + X = 37X
Upon adding the last 2 digits 7 and 3 we get 10 so the value of X will be 0
Hence, option E