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If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0, then
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04 Aug 2021, 07:05
04 Aug 2021, 07:05
Expert Reply
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Question Stats:
90% (00:41) correct
9% (00:35) wrong based on 11 sessions
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If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0, then x =
A. –4
B. –3
C. –2
D. –1
E. 0
A. –4
B. –3
C. –2
D. –1
E. 0
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0, then
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04 Aug 2021, 07:29
04 Aug 2021, 07:29
1
Carcass wrote:
If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0, then x =
A. –4
B. –3
C. –2
D. –1
E. 0
A. –4
B. –3
C. –2
D. –1
E. 0
Let's test the answer choices...
A) x = -4
The three values become (-4 + 2), (-4 + 4), and (-4 + 6)
Simplify to get: -2, 0 and 2
The average = (-2 + 0 + 2)/3 = 0/3 = 0
Perfect!
Answer: A
Cheers,
Brent
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Status:GRE Quant Tutor
Posts: 1141
Given Kudos: 9
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Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
GPA: 2.8
WE:Engineering (Computer Software)
If the average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0, then
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05 Aug 2022, 21:38
05 Aug 2022, 21:38
Theory
The average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0
Arithmetic Mean = \(\frac{Sum}{3}\) = \(\frac{x + 2 + x + 4 + x + 6}{3}\) = \(\frac{3x + 12 }{ 3}\) = 0 (given)
=> 3x + 12 = 3*0 = 0
=> 3x = -12
=> x = \(\frac{-12}{3}\) = -4
So, Answer will be A.
Hope it helps!
Watch the following video to Learn the Basics of Statistics
- ➡ Average or Arithmetic Mean = Sum of all the Values / Total Number of Values
The average (arithmetic mean) of x + 2, x + 4, and x + 6 is 0
Arithmetic Mean = \(\frac{Sum}{3}\) = \(\frac{x + 2 + x + 4 + x + 6}{3}\) = \(\frac{3x + 12 }{ 3}\) = 0 (given)
=> 3x + 12 = 3*0 = 0
=> 3x = -12
=> x = \(\frac{-12}{3}\) = -4
So, Answer will be A.
Hope it helps!
Watch the following video to Learn the Basics of Statistics
