rx10 wrote:
Oh! Wow. Nice question.
We are given that a=−1 & a−bc=1
Now
for a−bc=1 , the numerator cannot be 0
a−b≠0
−1−b≠0
b≠−1
Answer B
The denominator cannot be 0. The bottom part of the fraction because otherwise would be an indefinite fraction which is impossible on the GRE
Quote:
In this case, c can’t equal zero, so whatever value
is impossible for b must be the one that corresponds to c = 0.
To simplify the expression, multiply by c:
a − b = c
If a = −1, then −1 − b = c, or b = −c − 1. If c = 0, then b = −0 − 1 = −1.
So, since c cannot equal zero, b cannot equal -1, choice (B).