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If y^2=2, what is the value
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25 Aug 2021, 04:11
25 Aug 2021, 04:11
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If \(y^2=2\), what is the value \(\frac{2^{(x-y)(x+y)}}{2^{(x-1)(x+1)}}\) ?
(A) −2
(B) −1/2
(C) 1/2
(D) 2
(E) 4
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
(A) −2
(B) −1/2
(C) 1/2
(D) 2
(E) 4
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
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If y^2=2, what is the value
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25 Aug 2021, 04:18
25 Aug 2021, 04:18
1
Carcass wrote:
If \(y^2=2\), what is the value \(\frac{2^{(x-y)(x+y)}}{2^{(x-1)(x+1)}}\) ?
(A) −2
(B) −1/2
(C) 1/2
(D) 2
(E) 4
(A) −2
(B) −1/2
(C) 1/2
(D) 2
(E) 4
\(\frac{2^{(x-y)(x+y)}}{2^{(x-1)(x+1)}}\)
\(\frac{2^{(x^2 - y^2)}}{2^{(x^2 - 1)}}\)
\((\frac{2^{x^2}}{2^{y^2}})(\frac{2}{2^{x^2}})\)
\(\frac{2}{2^{y^2}}\)
Put \(y^2 = 2\);
\(\frac{2}{2^2} = \frac{2}{4} = \frac{1}{2}\)
Hence, option C
General Discussion
Re: If y^2=2, what is the value
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26 Aug 2021, 05:01
26 Aug 2021, 05:01
KarunMendiratta Sir I did not get the second step?can you plese explain.
Thank you
Thank you
