GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
In the figure above, Arc AD = Arc BC and AB is the diameter of the
[#permalink]
29 Aug 2021, 23:18
29 Aug 2021, 23:18
1
1
Bookmarks
00:00
Question Stats:
94% (01:41) correct
5% (01:49) wrong based on 17 sessions
Hide Show timer Statistics
Attachment:
Measure of Angle x.png [ 5.33 KiB | Viewed 2015 times ]
In the figure above, Arc AD = Arc BC and AB is the diameter of the circle.
Quantity A |
Quantity B |
x° |
20° |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
In the figure above, Arc AD = Arc BC and AB is the diameter of the
[#permalink]
31 Aug 2021, 21:18
31 Aug 2021, 21:18
Explanation:
Let Arc AD = Arc BC = \(y°\)
We know, AB is the diameter of circle O
So, Arc AD + Arc DC + Arc BC = \(180°\)
i.e. \(y° + 50° + y° = 180°\)
\(y = 65°\)
Thus, \(∠AOD = ∠BOC = 65°\)
Applying the property of Central Angle;
\(∠CAB = \frac{∠BOC}{2} = \frac{65°}{2} = 32.5°\)
Col. A: \(32.5°\)
Col. B: \(20°\)
Hence, option A
Let Arc AD = Arc BC = \(y°\)
We know, AB is the diameter of circle O
So, Arc AD + Arc DC + Arc BC = \(180°\)
i.e. \(y° + 50° + y° = 180°\)
\(y = 65°\)
Thus, \(∠AOD = ∠BOC = 65°\)
Applying the property of Central Angle;
\(∠CAB = \frac{∠BOC}{2} = \frac{65°}{2} = 32.5°\)
Col. A: \(32.5°\)
Col. B: \(20°\)
Hence, option A
Attachments
Measure of Angle x.png [ 7.78 KiB | Viewed 1753 times ]
General Discussion
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Given Kudos: 64
GRE 1: Q160 V152
In the figure above, Arc AD = Arc BC and AB is the diameter of the
[#permalink]
30 Aug 2021, 17:25
30 Aug 2021, 17:25
x=65 and answer is A
