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x+2/2=12/x
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01 Sep 2021, 10:07
01 Sep 2021, 10:07
Expert Reply
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Question Stats:
66% (00:54) correct
33% (01:24) wrong based on 33 sessions
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\(\frac{x+2}{2}=\frac{12}{x}\), and \(x \neq 0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
x |
5 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
x+2/2=12/x
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02 Sep 2021, 00:45
02 Sep 2021, 00:45
1
\(x^2 + 2x - 24 = 0\)
(x+6)(x-4) = 0
\(x = -6 / 4\)
For any value of \(x\), Qt B > Qt A
Answer B
(x+6)(x-4) = 0
\(x = -6 / 4\)
For any value of \(x\), Qt B > Qt A
Answer B
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Re: x+2/2=12/x
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02 Sep 2021, 06:14
02 Sep 2021, 06:14
3
Carcass wrote:
\(\frac{x+2}{2}=\frac{12}{x}\), and \(x \neq 0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
x |
5 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Given: \(\frac{x+2}{2}=\frac{12}{x}\)
Since the equation features an equation with one fraction equal to another fraction, we can cross multiply to get: \((x)(x+2)=(2)(12)\)
Simplify to get: \(x^2 + 2x=24\)
Subtract \(24\) from both sides: \(x^2 + 2x-24 = 0\)
Factor: \((x + 6)(x - 4)= 0\)
So, EITHER \(x = -6\) OR \(x = 4\)
If \(x = -6\), then Quantity B is greater.
If \(x = 4\), then Quantity B is greater.
In both possible cases, Quantity B is greater
Answer: B
