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A and B were each paid $D in advance to do a certain job together
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02 Sep 2021, 03:34
02 Sep 2021, 03:34
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Question Stats:
65% (02:46) correct
34% (02:19) wrong based on 41 sessions
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A and B were each paid \($D\) in advance to do a certain job together. A worked on the job for 10 hours and B worked 2 hours less than A. B gave A \($y\) of his payment so that they would receive the same hourly wage.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
Dollar amount (in terms of \(y\)) that A was paid in advance |
\(6y\) |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
A and B were each paid $D in advance to do a certain job together
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03 Sep 2021, 23:22
03 Sep 2021, 23:22
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Given that A works for 10 hours and B works for 8 hours for a job they are paid $D.
Assuming D is equal to $180, both should have been paid $90 each if they did equal amount of work. But since A worked more, B needs to give some part of their wage to A.
Hourly wage = $180/18 = $10 per hour.
Now, according to the amount of work they did, A should be paid $100 and B should be paid $80. Hence, B should give $10 from his pay to A to balance out the initial advance. This $10 is equal to y as per the question.
Quantity A = 9y (Initial amount received by A which is $90)
Quantity B = 6y (6 * 10 = $60)
Clearly, A is greater.
Assuming D is equal to $180, both should have been paid $90 each if they did equal amount of work. But since A worked more, B needs to give some part of their wage to A.
Hourly wage = $180/18 = $10 per hour.
Now, according to the amount of work they did, A should be paid $100 and B should be paid $80. Hence, B should give $10 from his pay to A to balance out the initial advance. This $10 is equal to y as per the question.
Quantity A = 9y (Initial amount received by A which is $90)
Quantity B = 6y (6 * 10 = $60)
Clearly, A is greater.
Re: A and B were each paid $D in advance to do a certain job together
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09 Nov 2023, 04:06
09 Nov 2023, 04:06
1
KarunMendiratta wrote:
A and B were each paid \($D\) in advance to do a certain job together. A worked on the job for 10 hours and B worked 2 hours less than A. B gave A \($y\) of his payment so that they would receive the same hourly wage.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
Dollar amount (in terms of \(y\)) that A was paid in advance |
\(6y\) |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
I solved this algebraically because it would have given me the fastest answer in terms of y (what the Q asked for).
So, both were given D dollars.
Hourly wage for A = D/10
Hourly wage for B = D/8
Now, D/8 - y = D/10
or D = 40y = Qty A
Qty A > Qty B.
