Re: Pipe A can fill a tank in 3 hours. If pipe B can fill the sa
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17 Mar 2019, 17:37
Pipe A can fill \(\frac{1}{3}\) of a tank in 1 hour. Pipe B can fill \(\frac{1}{2}\) of a tank in 1 hour.
Together, they can fill \(\frac{1}{3} + \frac{1}{2} = \frac{2}{6} + \frac{3}{6} = \frac{5}{6}\) of a tank in 1 hour.
Each minute, they'll fill \(\frac{1}{60}\) of what they can fill in an hour. So together, they can fill \(\frac{5}{360}\) of the tank in 1 minute.
How long will it take them to fill \(\frac{2}{3}\) of the tank? Algebraically:
\(\frac{5}{360}x = \frac{2}{3}\)
\(x = \frac{2}{3} \times \frac{360}{5} = \frac{240}{5} = 48\)