Carcass wrote:
A driver completed the first 20 miles of a 40-mile trip at an average speed of 50 miles per hour and the second 20 miles at an average speed of x miles per hour. The average speed for the entire 40-mile trip was 60 miles per hour. (Assume that the driver did not make any stops during the 40-mile trip.)
Quantity A |
Quantity B |
x-60 |
10 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Source:
manhattanreviewAverage speed
=totaldistancetravelledtotaltraveltimeThe driver travels a total distance of 40 miles, and were told that the average speed was 60 miles per hour.
Plug in those values to get:
60=40totaltraveltimeNow let's calculate
total travel timetotal travel time = (time spent driving the first 20 miles) + (time spent driving the last 20 miles)
Since
time=distancespeed, we get:
total travel time =2050+20xtotal travel time =20x50x+100050xtotal travel time =20x+100050xPlug this into our equation:
60=40(20x+100050x)Rewrite as follows:
60=(40)(50x20x+1000)Simplify:
60=2000x20x+1000Multiply both sides of the equation by
20x+1000 to get:
1200x+60,000=2000xSubtract
1200x from both sides to get:
60,000=800xDivide both sides by
800 to get:
75=xSo we have:
QUANTITY A:
x−60=75−60=15QUANTITY B:
10Answer: A