Jayz007 wrote:
The question is what if the tank is not half filled how to approach , when we find the radi in step 1 , then step 2 to find the height of surface above the ground , how would we approach it implies tha we might to have have the height of cylinder for that case if im correct
For any other volume it would be \(diameter \times \text{fraction of total volume filled}\).
Thus, if the cylinder was \(\frac{1}{3}\) rd filled, the height of the water would be \(diameter \times \frac{1}{3}\)
If the diameter is \(4\), the height of the water would be \(4 \times \frac{1}{3}\) = \(\frac{4}{3}\) meters