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Re: Set A arranged in ascending order of the values: [#permalink]
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rx10 wrote:
Carcass

Is something missing in the question? Set A detail?


See now GreenlightTestPrep rx10

Brent fixed it, kindly
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Re: Set A arranged in ascending order of the values: [#permalink]
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The Median of an even set of numbers is going to be the mean of 2 numbers in the middle so this median=(x-2)/2 and the mean is going to be (-6+X)/8 so by taking the possible values of X at the extremes (-2 and -5) we can compare the two quantities.

Possible values of X=-2
Median= -2
Mean= -1
Possible values of X=-5
Median= -7/2 =-3.5
Mean= -11/8 =-1.375
Since in both cases the Mean is greater than the median correct choice is A
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Re: Set A arranged in ascending order of the values: [#permalink]
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Jose123 wrote:
The Median of an even set of numbers is going to be the mean of 2 numbers in the middle so this median=(x-2)/2 and the mean is going to be (-6+X)/8 so by taking the possible values of X at the extremes (-2 and -5) we can compare the two quantities.

Possible values of X=-2
Median= -2
Mean= -1
Possible values of X=-5
Median= -7/2 =-3.5
Mean= -11/8 =-1.375
Since in both cases the Mean is greater than the median correct choice is A


Your solution is great. however, a minor error--the mean would actually be (-8+X)/8
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Re: Set A arranged in ascending order of the values: [#permalink]
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