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Of the 50 electronics components that a factory must manufacture, 70
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29 Sep 2021, 05:13
29 Sep 2021, 05:13
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65% (02:04) correct
34% (02:08) wrong based on 29 sessions
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Of the 50 electronics components that a factory must manufacture, 70 percent would be most efficiently manufactured by Machine A and the remaining 30 percent would be most efficiently manufactured by Machine B, though either machine could manufacture any of the 50 components. If 36 percent of the components were manufactured by Machine A and the remainder were manufactured by Machine B, what is the highest possible number of components that were manufactured by the machine that would manufacture them the most efficiently?
(A) 30
(B) 32
(C) 33
(D) 35
(E) 36
(A) 30
(B) 32
(C) 33
(D) 35
(E) 36
Re: Of the 50 electronics components that a factory must manufacture, 70
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30 Sep 2021, 03:21
30 Sep 2021, 03:21
Carcass,
The answer should be B. 32 because B manufactured 64% of the components. 50*64/100 = 32. Kindly, suggest why it is 33.
The answer should be B. 32 because B manufactured 64% of the components. 50*64/100 = 32. Kindly, suggest why it is 33.
Re: Of the 50 electronics components that a factory must manufacture, 70
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30 Sep 2021, 05:20
30 Sep 2021, 05:20
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Expert Reply
Quote:
If 36 percent of the components were manufactured by Machine A, it would maximize the number that are manufactured most efficiently to have all 36 percent of those components be among the 70 percent that A
manufactures most efficiently. That leaves 74 percent to be manufactured by B. 30 percent of the total are most efficiently manufactured by B, and all of those will be manufactured by B.
So, the total percent that is manufactured most efficiently is 36 (done by A) plus 30 (done by B), for a sum of 66%. There are only 50 components being manufactured, so the answer is 0.66(50) = 33, choice (C).
manufactures most efficiently. That leaves 74 percent to be manufactured by B. 30 percent of the total are most efficiently manufactured by B, and all of those will be manufactured by B.
So, the total percent that is manufactured most efficiently is 36 (done by A) plus 30 (done by B), for a sum of 66%. There are only 50 components being manufactured, so the answer is 0.66(50) = 33, choice (C).
