Carcass wrote:
10 members of a society, including members A and B, attended a meeting. 2 of these members were selected to form a committee. What is the probability that the 2 members selected were members A and B?
A. 1/10
B. 1/15
C. 1/20
D. 1/30
E. 1/45
Let's apply some
probability rulesP(A and B both selected) = P(1st selection is one member of the pair
AND 2nd selection is the other member of the pair)
= P(1st selection is one one member of the pair)
x P(2nd selection is the other member of the pair)
= 2/10
x 1/9
= 1/45
Answer: E