Carcass wrote:
If b, c, and h are constants such that
x2+bx+c=(x+h)2, what is the value of c if b = 10?
See more on these concepts our
GRE Quant Book and the
GRE Math Essentials projectGiven:
x2+bx+c=(x+h)2 Expand the right side to get:
x2+bx+c=x2+2hx+h2Substitute
b=10 to get:
x2+10x+c=x2+2hx+h2When we compare the two equations we can see that
10=2h, which we can solve to get
h=5Substitute
h=5 to get:
x2+10x+c=x2+2(5)x+52Evaluate to get:
x2+10x+c=x2+10x+25At this point it's clear that
x=25Answer:
25