Carcass wrote:
A closed cylindrical tank contains \(16\pi\) cubic feet of water and is filled to one-quarter of its capacity. When the tank is placed upright on its circular base on level ground, the height of the water in the tank is equal to the diameter of the tank’s base. What is the radius of the tank?
(A) 1
(B) 2
(C) 2√2
(D) 4
(E) 8
Given: Cylindrical tank is filled \(\frac{1}{4}\) when standing on it's base so \(\frac{\pi r^2h}{4} = 16\pi\)
\(r^2h = 64\)
Next, height of water = diameter => \(\frac{h}{4} = 2r\)
\(h = 8r\)
Substituting in the first equation: \(r^2*8r = 64 => r=2\)
Answer is B)