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Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1

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COolguy101
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Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 [#permalink] New post   28 Oct 2021, 21:27
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Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 jacket, 1 pant and 1 pair of shoes every day. However, 1 jacket and 1 pant don`t match, so they cannot be selected together. In such circumstances, for how many days can she wear differently?
A.19
B. 20
C. 21
D. 22
E. 23

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D
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kapil1
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Re: Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 [#permalink] New post   29 Oct 2021, 22:54
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Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 jacket, 1 pant and 1 pair of shoes every day. However, 1 jacket and 1 pant don`t match, so they cannot be selected together. In such circumstances, for how many days can she wear differently?


Number of ways in which 1 jacket, 1 pant and 1 pair of shoes can be selected = 4*3*2 = 24
Number of ways of selecting 1 jacket and 1 pant which don`t match = 1*1*2 = 2

Required number of ways = (Total number of ways) - (Number of ways in which jacket and pant dont match)
= 24 - 2 = 22

D is correct
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COolguy101
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Re: Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 [#permalink] New post   30 Oct 2021, 00:45
kapil1 wrote:
Quote:
Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 jacket, 1 pant and 1 pair of shoes every day. However, 1 jacket and 1 pant don`t match, so they cannot be selected together. In such circumstances, for how many days can she wear differently?


Number of ways in which 1 jacket, 1 pant and 1 pair of shoes can be selected = 4*3*2 = 24
Number of ways of selecting 1 jacket and 1 pant which don`t match = 1*1*2 = 2

Required number of ways = (Total number of ways) - (Number of ways in which jacket and pant dont match)
= 24 - 2 = 22

D is correct


I am confused in the highlighted line sir.
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kapil1
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Re: Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 [#permalink] New post   30 Oct 2021, 23:16
COolguy101 wrote:
kapil1 wrote:
Quote:
Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 jacket, 1 pant and 1 pair of shoes every day. However, 1 jacket and 1 pant don`t match, so they cannot be selected together. In such circumstances, for how many days can she wear differently?


Number of ways in which 1 jacket, 1 pant and 1 pair of shoes can be selected = 4*3*2 = 24
Number of ways of selecting 1 jacket and 1 pant which don`t match = 1*1*2 = 2

Required number of ways = (Total number of ways) - (Number of ways in which jacket and pant dont match)
= 24 - 2 = 22

D is correct


I am confused in the highlighted line sir.

This is a case of selecting together 1 jacket and 1 pant which don`t match, and a pair of shoes.
Hence, 1*1*2 = 2 ways
Subtracting this case from the total number of cases = 24 - 2 =22
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COolguy101
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Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 [#permalink] New post   31 Oct 2021, 03:50
Sir, if prompt says two jacket and 2 pant wont match , then what will be the final answer kapil1 sir
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babadook
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Re: Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 [#permalink] New post   02 Nov 2021, 01:52
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Shouldn't the answer be A, B, C, D ? because she can wear differently for 19, 20, 21, and 22 days. From the 23rd day onwards, she has to wear that forbidden pant-jacket combination. I think the wording of the question needs to be - what is the maximum possible number of days that she can wear differently , then answer D is correct.
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Re: Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 [#permalink] New post   26 Nov 2023, 06:28
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 [#permalink]
26 Nov 2023, 06:28
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