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An ice cream shop sells 9 different flavors of ice cream, including va
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01 Nov 2021, 06:43
01 Nov 2021, 06:43
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An ice cream shop sells 9 different flavors of ice cream, including vanilla and chocolate. If two different flavors are chosen at random to create a daily special, what is the probability that chocolate is chosen, but vanilla is not?
(A) \(\frac{7}{22}\)
(B) \(\frac{7}{36}\)
(C) \(\frac{1}{36}\)
(D) \(\frac{7}{12}\)
(E) \(\frac{1}{18}\)
(A) \(\frac{7}{22}\)
(B) \(\frac{7}{36}\)
(C) \(\frac{1}{36}\)
(D) \(\frac{7}{12}\)
(E) \(\frac{1}{18}\)
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Re: An ice cream shop sells 9 different flavors of ice cream, including va
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01 Nov 2021, 06:48
01 Nov 2021, 06:48
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Carcass wrote:
An ice cream shop sells 9 different flavors of ice cream, including vanilla and chocolate. If two different flavors are chosen at random to create a daily special, what is the probability that chocolate is chosen, but vanilla is not?
(A) \(\frac{7}{22}\)
(B) \(\frac{7}{36}\)
(C) \(\frac{1}{36}\)
(D) \(\frac{7}{12}\)
(E) \(\frac{1}{18}\)
(A) \(\frac{7}{22}\)
(B) \(\frac{7}{36}\)
(C) \(\frac{1}{36}\)
(D) \(\frac{7}{12}\)
(E) \(\frac{1}{18}\)
P(chocolate but not vanilla chosen) = P(1st scoop is chocolate AND 2nd scoop is NOT vanilla OR 1st scoop is neither chocolate nor vanilla AND 2nd scoop is chocolate)
= P(1st scoop is chocolate AND 2nd scoop is NOT vanilla) + P(1st scoop is neither chocolate nor vanilla AND 2nd scoop is chocolate)
= (1/9 x 7/8) + (7/9 x 1/8)
= 7/72 + 7/72
= 14/72
= 7/36
Answer: B
gmatclubot
Re: An ice cream shop sells 9 different flavors of ice cream, including va [#permalink]
01 Nov 2021, 06:48
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