Re: If x < y < z and y - x > 5, where x is an even integer and y and z are
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21 Jul 2022, 00:28
Solution -
y is odd and x is even, so (y - x) has to be odd. ( y - x ) > 5 means ( y - x ) can have a value of 7.
y - x = 7;
=> y = x + 7
The main equation will become,
x < (x + 7) < z
Subtract x from all,
0 < 7 < (z - x)
Since z is odd and x is even, (z - x) has to be odd.
As (z - x) > 7, the least possible value of (z - x) will be 9.
Answer D