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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2508
Given Kudos: 1053
GPA: 3.39
If n is a positive integer, how many of the ten digits from 0 through
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25 Nov 2021, 04:09
25 Nov 2021, 04:09
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Question Stats:
50% (01:47) correct
50% (01:31) wrong based on 4 sessions
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If n is a positive integer, how many of the ten digits from 0 through 9 could be the units digits of n^3 ?
A. Three
B. Four
C. Six
D. Nine
E. Ten
A. Three
B. Four
C. Six
D. Nine
E. Ten
Re: If n is a positive integer, how many of the ten digits from 0 through
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26 Nov 2021, 06:07
26 Nov 2021, 06:07
Expert Reply
If n is a positive integer, how many of the ten digits from 0 through 9 could be the units digits of n^3 ?
A. Three
B. Four
C. Six
D. Nine
E. Ten
The question is fairly straightforward, it basically asks: which digits can be the units digit of a perfect cube.
Can it be 0? Yes, 10^3=1,000.
Can it be 1? Yes, 1^3=1.
Can it be 2? Yes, 8^3=512.
Can it be 3? Yes, 7^3=343.
Can it be 4? Yes, 4^3=64.
Can it be 5? Yes, 5^3=125.
Can it be 6? Yes, 6^3=...6.
Can it be 7? Yes, 3^3=27.
Can it be 8? Yes, 2^3=8.
Can it be 9? Yes, 9^3=...9.
Answer: E.
A. Three
B. Four
C. Six
D. Nine
E. Ten
The question is fairly straightforward, it basically asks: which digits can be the units digit of a perfect cube.
Can it be 0? Yes, 10^3=1,000.
Can it be 1? Yes, 1^3=1.
Can it be 2? Yes, 8^3=512.
Can it be 3? Yes, 7^3=343.
Can it be 4? Yes, 4^3=64.
Can it be 5? Yes, 5^3=125.
Can it be 6? Yes, 6^3=...6.
Can it be 7? Yes, 3^3=27.
Can it be 8? Yes, 2^3=8.
Can it be 9? Yes, 9^3=...9.
Answer: E.
gmatclubot
Re: If n is a positive integer, how many of the ten digits from 0 through [#permalink]
26 Nov 2021, 06:07
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