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If 10^50 – 74 is written as an integer in base 10 notation what is the
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25 Nov 2021, 05:27
25 Nov 2021, 05:27
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If \(10^{50} – 74\) is written as an integer in base 10 notation, what is the sum of the digits in that integer?
A. 424
B. 433
C. 440
D. 449
E. 467
A. 424
B. 433
C. 440
D. 449
E. 467
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Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If 10^50 – 74 is written as an integer in base 10 notation what is the
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25 Nov 2021, 05:30
25 Nov 2021, 05:30
2
Carcass wrote:
If \(10^{50} – 74\) is written as an integer in base 10 notation, what is the sum of the digits in that integer?
A. 424
B. 433
C. 440
D. 449
E. 467
A. 424
B. 433
C. 440
D. 449
E. 467
One approach is to look for a pattern...
10^3 - 74 = 1,000 - 74 = 926 (1 nine)
10^4 - 74 = 10,000 - 74 = 9926 (2 nines)
10^5 - 74 = 100,000 - 74 = 99926 (3 nines)
10^6 - 74 = 1,000,000 - 74 = 999926 (4 nines)
.
.
.
In general, we can see that 10^n - 74 will feature n-2 9's followed by 26
So, 10^50 - 74 will feature 48 9's followed by 26
This means the sum of its digits = 48(9) + 2 + 6 = 432 + 2 + 6 = 440\
Answer: C
General Discussion
Re: If 10^50 74 is written as an integer in base 10 notation what is the
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16 Aug 2024, 16:19
16 Aug 2024, 16:19
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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