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ab+b^2/b or a+b

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Carcass
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ab+b^2/b or a+b [#permalink] New post   03 Dec 2021, 06:52
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\(b \neq 0\)

Quantity A
Quantity B
\(\frac{ab+b^2}{b} \)
\( a+b\)



A. The quantity on the left is greater
B. The quantity on the right is greater
C. Both are equal
D. The relationship cannot be determined without further information
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C
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Re: ab+b^2/b or a+b [#permalink] New post   03 Dec 2021, 20:20
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Multiply both the quantities with \(b\)

Qt A = Qt B = \(ab+b^2\)

Answer \(C\)
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ab+b^2/b or a+b [#permalink] New post   04 Dec 2021, 06:58
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Carcass wrote:
\(b \neq 0\)

Quantity A
Quantity B
\(\frac{ab+b^2}{b} \)
\( a+b\)



A. The quantity on the left is greater
B. The quantity on the right is greater
C. Both are equal
D. The relationship cannot be determined without further information


Useful (and often tested) property: \(\frac{a+b}{c} = \frac{a}{c} + \frac{b}{c}\)

Apply this property to Quantity A to get:
QUANTITY A: \(\frac{ab}{b}+\frac{b^2}{b} \)
QUANTITY B: \( a+b\)

Simplify Quantity A to get:
QUANTITY A: \(a+b\)
QUANTITY B: \( a+b\)

Answer: C
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Re: ab+b^2/b or a+b [#permalink] New post   04 Dec 2021, 10:27
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Quantity A

\(\frac{ab+b^2}{b} \)

Taking b common in numerator we get

\(\frac{b*(a+b)}{b}\)

Cancelling b in numerator and denominator we get

Quantity A = a+b, which is equal to Quantity B

So, Answer will be C
Hope it helps!
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Re: ab+b^2/b or a+b [#permalink]
04 Dec 2021, 10:27
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