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14/42^4 or 1/3*2/9

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14/42^4 or 1/3*2/9 [#permalink] New post   28 Dec 2021, 06:21
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Question Stats:

60% (00:58) correct 40% (01:09) wrong based on 40 sessions

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Quantity A
Quantity B
\((\frac{14}{42})^4 \)
\(\frac{1}{3} \times \frac{2}{9} \times \frac{3}{(-6)} \times \frac{(-1)}{3}\)




The quantity in Column A is greater
The quantity in Column B is greater
The two quantities are equal
The relationship cannot be determined from the information given
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C
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GRE 1: Q168 V157

GRE 2: Q167 V161
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14/42^4 or 1/3*2/9 [#permalink] New post   28 Dec 2021, 10:17
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Qt A

\((\frac{14}{42})^4 \)

\(3^{-4}\)

Qt B

\(\frac{1}{3} × \frac{2}{9} × \frac{3}{(−6)} × \frac{(−1)}{3}\)

\(\frac{2}{27} * \frac{1}{6}\)

\(\frac{1}{81}\)

\(3^{-4}\)

Qt A = Qt B

Answer C
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gmatclubot
14/42^4 or 1/3*2/9 [#permalink]
28 Dec 2021, 10:17
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