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The positive integer n is divisible by 7. If n 2 is greater than 1000,
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17 Aug 2021, 02:40
17 Aug 2021, 02:40
Expert Reply
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Question Stats:
71% (01:41) correct
28% (01:38) wrong based on 28 sessions
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The positive integer n is divisible by 7. If \(n^2\) is greater than 1000, which of the following is the smallest possible value of \(\frac{n}{7} \)?
(A) 3.5
(B) 4
(C) 4.5
(D) 5
(E) 6
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
(A) 3.5
(B) 4
(C) 4.5
(D) 5
(E) 6
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
The positive integer n is divisible by 7. If n 2 is greater than 1000,
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17 Aug 2021, 08:10
17 Aug 2021, 08:10
\(n\), positive integer, is a multiple of \(7\) with \(n^2 > 1000\)
The smallest possible value \(n\) can take \(= 35\)
\(\frac{n}{7} \) = \(\frac{35}{7} = 5\)
Answer D
The smallest possible value \(n\) can take \(= 35\)
\(\frac{n}{7} \) = \(\frac{35}{7} = 5\)
Answer D
Re: The positive integer n is divisible by 7. If n 2 is greater than 1000,
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14 Jan 2022, 13:40
14 Jan 2022, 13:40
This is how I solved it.
If n^2 is greater than 1000, then if you find the square roots of both sides, you get that n has to be greater than the square root of 1000
The square root of 1000 is around 31.6
n > 31.6
if you divide n by 7 you have to do the same to the 31.6
(n/7)> (31.6/7)
(n/7) > 4.52
so any value greater than 4.52 should work:
D: 5 ----> 5 = n/7 ---> 5(7) = n ---> 35 = n ---> 35^2 = n^2 ----> 1225 = n^2, this is greater than 1000 so it works !
E: 6 ----> 6 = n/7 ---> 6(7) = n ---> 42 = n ---> 42^2 = n^2 ----> 1764 = n^2, this is greater than 1000 so it also works!
the smaller value is the answer so D would be the solution.
If n^2 is greater than 1000, then if you find the square roots of both sides, you get that n has to be greater than the square root of 1000
The square root of 1000 is around 31.6
n > 31.6
if you divide n by 7 you have to do the same to the 31.6
(n/7)> (31.6/7)
(n/7) > 4.52
so any value greater than 4.52 should work:
D: 5 ----> 5 = n/7 ---> 5(7) = n ---> 35 = n ---> 35^2 = n^2 ----> 1225 = n^2, this is greater than 1000 so it works !
E: 6 ----> 6 = n/7 ---> 6(7) = n ---> 42 = n ---> 42^2 = n^2 ----> 1764 = n^2, this is greater than 1000 so it also works!
the smaller value is the answer so D would be the solution.
