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Re: In the x-y coordinate plane, lines J, K and L are defined [#permalink]
i have done it in a long method, finding the intersection points and then gettin the slope.

Easier method anybody?

Thanks
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Re: In the x-y coordinate plane, lines J, K and L are defined [#permalink]
Point B lies on line J as well, why aren't we considering slope of line J & L?

GreenlightTestPrep wrote:
GreenlightTestPrep wrote:
Line J: 4x - 7 = 6y
Line K: 6y + 3x = -2
Line L: 2x = 5 - y

In the x-y coordinate plane, lines J, K and L are defined by the above equations.
Point B is the point of intersection of lines J and K. Point C is the point of intersection of lines K and L.
What is the slope of line segment BC?

A) -3/2
B) -2/3
C) -1/2
D) 1/2
E) 2/3



Key Concepts: point B lies on line K, and point C lies on line K
Since both points lie on line K, the slope between points B and C will be the same as the slope of line K.


To find the slope of line K, let's take the equation of line K (6y + 3x = -2), and rewrite it in slope y-intercept form (y = mx + b)
Take: 6y + 3x = -2
Subtract 3x from both sides to get: 6y = -3x - 2
Divide both sides by 6 to get: y = (-3/6)x - 2/6
Simplify to get: y = (-1/2)x - 1/3

So, line K has a slope of -1/2 and a y-intercept of -1/3

Answer: C

Cheers,
Brent
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Re: In the x-y coordinate plane, lines J, K and L are defined [#permalink]
1
Chaithraln2499 wrote:
Point B lies on line J as well, why aren't we considering slope of line J & L?


The key here is that points B and C both lie on line K.
So, the slope between points B and C will be the same as the slope of line K

The problem with your suggestion is that, while point B lies on line J, point C does NOT lie on line J, which means we can't use the same shortcut as we used above.

Does that help?
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Re: In the x-y coordinate plane, lines J, K and L are defined [#permalink]
Got it! Thanks!

GreenlightTestPrep wrote:
Chaithraln2499 wrote:
Point B lies on line J as well, why aren't we considering slope of line J & L?


The key here is that points B and C both lie on line K.
So, the slope between points B and C will be the same as the slope of line K

The problem with your suggestion is that, while point B lies on line J, point C does NOT lie on line J, which means we can't use the same shortcut as we used above.

Does that help?
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Re: In the x-y coordinate plane, lines J, K and L are defined [#permalink]
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