----------ASIDE----------------------------------------
If the prime factorization of N = (p^a)(q^b)(r^c) . . . (where p, q, r, etc are different prime numbers), then N has a total of (a+1)(b+1)(c+1)(etc) positive divisors.

Example: 14000 = (2^4)(5^3)(7^1)
So, the number of positive divisors of 14000 = (4+1)(3+1)(1+1) =(5)(4)(2) = 40
---ONTO THE QUESTION!--------------------------------

54 = (2)(3)(3)(3)
= (2^1)(3^3)
So, the number of positive divisors of 54 = (1+1)(3+1) =(2)(4) = 8

Answer: C

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ALTERNATIVELY, we can just list all of the factors to get: {1, 2, 3, 6, 9, 18, 27, 54}
8 factors
Answer: C