Carcass wrote:
There are 12 pens and 5 pencils in box A. An object is picked at random from box A and moved to box B, in which there are already 4 pens and 5 pencils. If one object is then to be picked from box B, what is the probability that a pen will be picked?
A. \(\frac{8}{17}\)
B. \(\frac{80}{153}\)
C. \(\frac{9}{17}\)
D. \(\frac{12}{17}\)
E. \(\frac{14}{17}\)
P(pen from box B) = P(pen from A
AND pen from B
OR pencil from A
AND pen from B)
= P(pen from A
AND pen from B)
+ P(pencil from A
AND pen from B)
= [P(pen from A)
x P(pen from B)]
+ [P(pencil from A)
x P(pen from B)]
= [12/17
x 5/10]
+ [5/17
x 4/10]
= 60/170
+ 20/170
= 80/170
= 8/17
Answer: A