GreenlightTestPrep wrote:
After driving to a riverfront parking lot, Bob plans to run south along the river, turn around, and return to the parking lot, running north along the same path. After running 3.25 miles south, he decides to run for only 50 minutes more. If Bob runs at a constant rate of 8 minutes per mile, how many miles farther south can he run and still be able to return to the parking lot in 50 minutes?
(A) 1.5
(B) 2.25
(C) 3.0
(D) 3.25
(E) 4.75
Source: GMAT Official Guide
Let's sketch the situation:
If we let
x = the extra distance Bob jogs south, then.....
... he must travel the same
x miles north PLUS the additional
3.25 miles.
So the total distance Bob travels (AFTER jogging 3.25 miles south) =
x +
x +
3.25 miles
=
2x + 3.25 miles.
Since Bob's jogging speed is 8 minutes per mile, we can say that he travels 1 mile in 8 minutes.
So his speed = distance/time =
1/8 miles per minute.
Finally, Bob wants his remaining travel time to be 50 minutes.
Remaining travel time = (remaining distance)/(jogging speed)Plug in our values to get:
50 = (
2x + 3.25)/(
1/8)
Simplify:
50 = (2x + 3.25)(8)Expand:
50 = 16x + 26Subtract 26 from both sides:
24 = 16xSolve:
x = 24/16 = 3/2 = 1.5So, Bob can run an additional 1.5 miles.
Answer: A