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N is an integer such that 5999 < N < 8001, and each digit of N is eith
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15 Feb 2022, 06:59
15 Feb 2022, 06:59
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N is an integer such that 5999 < N < 8001, and each digit of N is either 0 or 2 or 4 or 6 or 8 only. How many values of N are possible?
A. 25
B. 125
C. 126
D. 250
E. 251
A. 25
B. 125
C. 126
D. 250
E. 251
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Re: N is an integer such that 5999 < N < 8001, and each digit of N is eith
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15 Feb 2022, 07:16
15 Feb 2022, 07:16
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Carcass wrote:
N is an integer such that 5999 < N < 8001, and each digit of N is either 0 or 2 or 4 or 6 or 8 only. How many values of N are possible?
A. 25
B. 125
C. 126
D. 250
E. 251
A. 25
B. 125
C. 126
D. 250
E. 251
Let's consider two possible cases:
Case 1: Numbers in the form 6???
Case 2: Numbers in the form 8???
Case 1: Numbers in the form 6???
We have 5 options (0, 2, 4, 6, or 8) for the hundreds digit.
We have 5 options (0, 2, 4, 6, or 8) for the tens digit.
We have 5 options (0, 2, 4, 6, or 8) for the units digit.
So, the total number of integers in the form 6??? = (5)(5)(5) = 125
Case 2: Numbers in the form 8???
Since N < 8001, we can see that 8000 is only possible number in the form 8???
So, the total number of integers in the form 8??? = 1
So, the number of values of N = 125 + 1 = 126
Answer: C
gmatclubot
Re: N is an integer such that 5999 < N < 8001, and each digit of N is eith [#permalink]
15 Feb 2022, 07:16
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